Question

29.............................​

Answer 1

Explicație pas cu pas:

$f( \sqrt{2} - 1) = -3( \sqrt{2} - 1) + 2 = - 3 \sqrt{2} + 3 + 2 = - 3 \sqrt{2} + 5$

$f( \sqrt{2} ) = -3 \sqrt{2} + 2$

$5 - 3 \sqrt{2} > 2 - 3 \sqrt{2} \\ \implies f( \sqrt{2} - 1) > f( \sqrt{2})$

Answer 2

$f( \sqrt{2} - 1) = - 3( \sqrt{2} - 1) + 2 = - 3 \sqrt{2} + 5$

$f( \sqrt{2} ) = - 3 \sqrt{2} + 2$

Rezulta :

$f( \sqrt{2} - 1) > f( \sqrt{2} )$