Question

(2la n+2+2la n+1+2la n):2la n-5​

Answer 1

Explicație pas cu pas:

$2 {}^{n + 2} + 2 {}^{n + 1} + 2 {}^{n} \div 2 {}^{n - 5} = \\ 2 {}^{n} \times (2 {}^{2} + 2 + 1) \div 2 {}^{n - 5} = \\ 2 {}^{n} \times 7 \div 2 {}^{n - 5} = \\2 {}^{n - n + 5} \times 7 = \\ 2 {}^{ 5} \times 7 = \\224$