Question

(2x+1)^2-(2x+1)(2x-1)+(x-3)(x+1)=(x+1)^2-2
AM NEVOIE DE AJUTOOOR VA ROG

Answer 1

Răspuns:

ai uitat sa spui daca e ecuatie sau identitate

adiva NU NE -AI DAT CERINTA

Explicație pas cu pas:

4x²+4x+1-(4x²-1)+x²-2x-3=x²+2x+1-2

4x+2+x²-2x-3=x²+2x-1

4x-2x+2-3=2x-1

2x-1=2x-1

x∈R

IDENTITATE

propabil ca se cerea

sa se arate ca

Answer 2

(2x+1)^2-(2x+1)(2x-1)+(x-3)(x+1)=(x+1)^2-2

$\it (2x+1)^2-(2x+1)(2x-1)+(x-3)(x+1)=(x+1)^2-2\Leftrightarrow \\ \\  \Leftrightarrow (2x+1)^2-(2x+1)(2x-1)+2=(3-x)(x+1)+(x+1)^2\Leftrightarrow\\ \\ \Leftrightarrow (2x+1)(2x+1-2x+1)-2=(x+1)(3-x+x+1) \Leftrightarrow \\ \\ \Leftrightarrow(2x+1)\cdot2+2=(x+1)\cdot4 \Leftrightarrow 4x+2+2=4x+4\Leftrightarrow4x+4=4x+4\ (A)$