Question

(2x-1)^{2} - (x+2)^{2} + (x+1)(x-1)-3(x^{2} -5)

Answer 1

${(2x - 1)}^{2} - {(x + 2)}^{2} + (x + 1)(x - 1) - 3( {x}^{2} - 5)$

$= 4 {x}^{2} - 4x + 1 - {x}^{2} - 4x - 4 + {x}^{2} - 1 - 3 {x}^{2} + 15$

$= {x}^{2} - 8x + 11$