Question

(3 √2 - 2 √3)x(√18+√12):(√75-√27)=
[(√2-√3)$^{2}$-(2√2-√3)$x^{2}$]x(6+2√6)+12=
REPEDE

Answer 1

(3√2-2√3) * (3√2+2√3) : (5√3-3√3) = [(3√2)² - (2√3)²] : 2√3=
(18-12) : 2√3= 6:2√3=3:√3 = 3√3/3=√3

(√2-√3-2√2+√3) * ( √2-√3+2√2-√3) * (6+2√6) +12=
=(-√2)*(3√2-2√3)*(6+2√6) +12=
= (-6+2√6)*(6+2√6)+12=
=(2√6)² - 6²+12=
=24-36+12=
=0