Question

(3 * 2 la puterea 2004-2 la puterea 2005) : 4 la puterea 1001



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Va rog ajutati-ma!

Answer 1

4^1001=(2^2)^1001=2^2002; (3×2^2004-2^2005)÷4^1001= 3×(2^2004÷2^2002)-(2^2005÷2&2002)= 3×2^2-2^3=3×4-8=12-8=4. " ^ " -este ridicat la putere.