Question

[(3+3)×3-3+3×(3+3÷3)]÷3-3×3+3÷3×1=​

Answer 1

Explicație pas cu pas:

[(3+3)×3-3+3×(3+3÷3)]÷3-3×3+3÷3×1=

=[6×3-3+3×(3+1)]÷3-9+1×1=

=(18-3+3x4):3-9+1=

=(18-3+12):3-9+1=

=(15+12):3-9+1=

=27:3-9+1=

=9-9+1=

=0+1=

=1

Answer 2

Răspuns:

$\red{ \large \boxed {1 \ \: }}$

Explicație pas cu pas:

Buna!!

•[(3+3)×3-3+3×(3+3:3)]:3-3×3+3:3×1=

=[6×3-3+3×(3+1)]:3-9+1×1=

=(18-3+3×4):3-9+1=

=(15+12):3-9+1=

=27:3-9+1=

=9-9+1=

=0+1=

=1 ✅

Succes !!;)

✿❀AndreeaBrainly123❀✿