Question

3+3×[3+3×(3+3×3)]=(3×a+3)×3+3
VA ROOOG DE CLASA IV​

Answer 1

Răspuns:

3+3×[3+3×(3+3×3)]=(3×a+3)×3+3

3+3×(3+3×12)=9a+9+3

3+3×39=9a+12

120-12=9a

108=9a

a=12

Answer 2

Rezolvare:
3+3x[3+3x(3+9)]=(3xa+3)x3+3
3+3x(3+3x12) =(3xa+3)x3+3
3+3x(3+36) =(3xa+3)x3+3
3+3x39 =(3xa+3)x3+3
3+117 =(3xa+3)x3+3
120 =(3xa+3)x3+3
(3xa+3)x3=120-3
(3xa+3)x3=117
(3xa+3)=117:3
3xa+3=39
3xa=39-3
3xa=36
a=36:3
a=12