Question

3+3x[( a+3)x3+3]=102
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Answer 1

$\displaystyle 3+3 \cdot [(a+3) \cdot 3+3]=102 \\ 3+3 \cdot (3a+9+3)=102 \\ 3+3 \cdot (3a+12)=102 \\ 3+9a+36=102 \\ 9a=102-3-36 \\ 9a=63 \\ a= \frac{63}{9} \\ a=7$