Question

impartiti numarul 4625 in parti invers proportionale cu 8,12 si 10

Answer 1

$8a=12b=10c=k \\ 8a=k \\ a=\frac{k}{8} \\ 12b=k \\ b=\frac{k}{12} \\ 10c=k \\ c=\frac{k}{10} \\ a+b+c=4625 \\ \frac{k}{8}+\frac{k}{12}+\frac{k}{10}=4625 \\ 15k+10k+12k=555000 \\ 37k=555000 \\ k=\frac{555000}{37} \\ k=15000 \\ a=\frac{k}{8}=\frac{15000}{8}=1875 \\ \\ b=\frac{k}{12}= \frac{15000}{12}=1250 \\ c=\frac{k}{10}=\frac{15000}{10}=1500$