Question

3+3x[( a+3)x3+3]=102 AJUTA-TI-MA VA ROG DAU CORONITA!!

Answer 1

$\displaystyle 3+3 \cdot [(a+3) \cdot 3+3]=102 \\ 3+3 \cdot (3a+9+3)=102 \\ 3+3 \cdot (3a+12)=102 \\ 3+9a+36=102 \\ 9a=102-3-36 \\ 9a=63 \\ a= \frac{63}{9} \\ a=7$