Question

[3^44:(3^10+3^10+3^10)^4+7^0]^51:2^50.va rog e urgent dau 50 de puncte
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Answer 1

Răspuns:

[3^44:(3^10+3^10+3^10)^4+7^0]^51:2^50=

[3⁴⁴:(3¹⁰·3)⁴+7⁰]⁵¹:2⁵⁰=

[3⁴⁴:(3¹¹)⁴+1]⁵¹:2⁵⁰=

(3⁴⁴:3⁴⁴+1)⁵¹:2⁵⁰=

2⁵¹:2⁵⁰=

2⁵¹⁻⁵⁰=

2¹=2

Answer 2

Răspuns: $\bf \red{\underline{~2~}}$

Explicație pas cu pas:

$\bf \Big[3^{44}:\big(3^{10}+3^{10}+3^{10}\big)^4+7^0\Big]^{51}:2^{50}=$

$\bf \Big[3^{44}:\big[3^{10}\cdot\big(3^{10-10}+3^{10-10}+3^{10-10}\big)\big]^4+1\Big]^{51}:2^{50}=$

$\bf \Big[3^{44}:\big[3^{10}\cdot\big(3^{0}+3^{0}+3^{0}\big)\big]^4+1\Big]^{51}:2^{50}=$

$\bf \Big[3^{44}:\big[3^{10}\cdot\big(1+1+1\big)\big]^4+1\Big]^{51}:2^{50}=$

$\bf \Big[3^{44}:\big(3^{10}\cdot 3 \big)^4+1\Big]^{51}:2^{50}=$

$\bf \Big[3^{44}:\big(3^{10+1} \big)^4+1\Big]^{51}:2^{50}=$

$\bf \Big(3^{44}:3^{11\cdot 4}+1\Big)^{51}:2^{50}=$

$\bf \Big(3^{44}:3^{44}+1\Big)^{51}:2^{50}=$

$\bf \Big(3^{44-44}+1\Big)^{51}:2^{50}=$

$\bf \Big(3^{0}+1\Big)^{51}:2^{50}=$

$\bf \big(1+1\big)^{51}:2^{50}=$

$\bf 2^{51}:2^{50}= 2^{51-50}=$

$\bf 2^{1}= \red{\underline{~2~}}$

$==pav38==$