Question

3√5-7x{√2+[15√5-3(√5 -4√2)]:12} Imi trebuie rezolvare completaa!!

Answer 1

3√5-7x{√2+[15√5-3(√5 -4√2)]:12}=
=3√5-7x[√2+(15√5-3√5 +12√2)]:12}=
=3√5-7x[√2+(12√5 +12√2)]:12}=
=3√5-7x(√2+√5 +√2)=
=3√5-7√5-14√2=-4√5-14√2

Answer 2

3√5-7x{√2+[15√5-3(√5 -4√2)]:12} =3√5-7x{√2+[15√5-3√5 +12√2)]:12}= 3√5-7x[√2+(15√5-3√5 +12√2):12]= 3√5-7x[√2+(12√5 +12√2):12]= 3√5-7x[√2+12(√5 +√2):12]= 3√5-7x(√2+√5 +√2)= 3√5-7x(2√2+√5 )= 3√5-14√2-7√5 = -4√5-14√2=-2(2√5+7√2)