Question

3/5 x la puterea5 + 3/4 x la puterea 4- 2X la puterea 3-1
f’(x)=?

Answer 1

$f`(x) =( \frac{3}{5} x^{5}+ \frac{3}{4}x^{4}- 2x^{3} -1 )`= \\\frac{3}{5}(x^{5})` + \frac{3}{4}(x^{4})~- 2(x^{3})` -1` =\\ \frac{3}{5}* 5x^{4} + \frac{3}{4}* 4x^{3} -2*3x^{2} = \\3x^{4} + 3x^{3} -6x^{2} = 3(x^{4} +x^{3}-2x^{2} )$