Question

3×(56-a)+(a-56):1+17×3+27:3=60
72:2-a+a+0:a=a×a
(a-16)×(b-16)×(c-16)=(30:6)×(36:6)×(40:10) astfel incat b

Answer 1

3×(56-a)+(a-56):1+17×3+27:3=60
168-3a+(a-56)+51+9=60
168-3a+a-56+51+9=60
172-2a=60
-2a=60-172
-2a=112
a=56



72:2-a+a+0:a=a×a
36=a la puterea a 2
atat am stiut cu placere