Question

3. aflati toate numerele care impartite la 8 dau catul 27
4. calculati media dicheama a numerele 8 si 24

Answer 1

3. d:8=27 si rest intre 0si 7 deoarece r<i adica r<8
d=27x8+r
r=0⇒d=27x8+0=216
r=1⇒d=27x8+1=217
r=2⇒d=27x8+2=218
r=3⇒d=27x8+3=219
r=4⇒d=27x8+4=220
r=5⇒d=27x8+5=221
r=6⇒d=27x8+6=222
r=7⇒d=27x8+7=223
Numerele cautate sunt:216,217,218,219,220,221,222,223
4.
ma=(8+24):2=32:2=16
mg=√8x24=√192=8√3

Answer 2

3. d:8=27 si rest intre 0si 7 deoarece r<i adica r<8
d=27x8+r
r=0⇒d=27x8+0=216
r=1⇒d=27x8+1=217
r=2⇒d=27x8+2=218
r=3⇒d=27x8+3=219
r=4⇒d=27x8+4=220
r=5⇒d=27x8+5=221
r=6⇒d=27x8+6=222
r=7⇒d=27x8+7=223
Numerele cautate sunt:216,217,218,219,220,221,222,223
4.
ma=(8+24):2=32:2=16
mg=√8x24=√192=8√3       

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