Question

(3 la 4-2 la 4×5)la 2019-(4 la 3-2 la 6) la 2020+2 la 1 la 5-7 la 0 la 5=​

Answer 1

Răspuns: 2¹ = 2

$\Big( 3^{4}-2^{4}\cdot5\Big)^{2019}-\Big(4^{3}-2^{6}\Big)^{2020} + 2{^{1}}^{5}-7{^{0}}^{5}=\\\\\Big( 81-16\cdot5\Big)^{2019}-\Big((2^{2}) ^{3}-2^{6}\Big)^{2020} + 2^{1} - 7^{0}=\\\\\Big( 81-80\Big)^{2019}-\Big(2^{2\cdot3}-2^{6}\Big)^{2020} + 2 - 1=\\\\1^{2019}-(2^{6}-2^{6})^{2020}+2-1=\\\\1-0^{2020}+2-1=\\\\1-0+2-1=\\\\\boxed{2}\: = \: \boxed{2^{1}}$