Question

3 nr consecutive au suma egala cu 45 determinați nr

Answer 1

a+b+c=45
b=a+1
c=a+2

=> a+a+1+a+2=45
=> 3×a+3=45
=> 3×a=42
=> a=42÷3
=> a=14
=> b=14+1=15
=> c=14+2=16

Answer 2

cele 3 numere consecutive sunt notate cu : a ; b=a+1; c=a+2
a+(a+1)+(a+2)=45
3a+3=45⇒3a=45-3⇒3a=42⇒a=14
daca a=14, b=14+1=15 si c=14+2=16
deci numerele sunt 14,15 si 16
verificare
14+15+16=45