Question

(3 rad din 2 + rad din 3 ) la a 2a

Answer 1

$(3 \sqrt{2} + \sqrt{3} )^2=(3 \sqrt{2} )^2+2 \cdot 3 \sqrt{2} \cdot \sqrt{3} + \sqrt{3} ^2= \\ =18+6 \sqrt{6} +3=21+6 \sqrt{6}$