Question

3. Rezolvati sistemul:

[tex]\left \{ {{ \frac{2x+y}{5}-{ \frac{2x+y}{8} = 1 \left \{ {{ \frac{2x-y}{6}+{ \frac{x-2y}{7} = 1 [/tex]

Answer 1

16x+8y-10x-5y=40
14x-7y+6x-12y=42

6x+3y=40   x=(40-3y)/6
20x-19y=42

20.(40-3y)/6-19y=42
400-30y-57y=126
-87y=-274
y=274/87
x=(40-3.274/87)/6=443/58