Question

3)Se introduc in apa 250 g de sare,rezultand 2 litri de saramura cu p=1,2 g/cm cub. Care va fi concentratia solutiei obtinute?

Answer 1

c=?
p=1,2g/cm cub
md=250 g
Vs=2000ml=2000cm cubi
p=$\frac{ms}{Vs}$
ms=p*Vs
ms=1,2g/cm cub*2000cm cubi
ms=2400g
c=$\frac{md*100}{ms}$
c=$\frac{250*100}{2400}$
c=10,4%