Question

3 (x+1)asupra lui 3=5 (1-x)asupra lui 5 -2 (3x-2)asupra lui 6 +2

Answer 1

$\frac{3(x + 1)}{3} = \frac{5(1 - x)}{5} - \frac{2(3x - 2)}{6} + 2$
$x + 1 = 1 - x - \frac{3x - 2}{3} + 2$
$2x - 2 = -\frac{3x - 2}{3}$
$3 \times (2x - 2) = -(3x - 2)$
$6x - 6 = -3x + 2$
$9x = 8$
$x = \frac{8}{9}$