Question

√3(x-2)+2√3(x+1)=6√3

Answer 1

[tex]\sqrt{3}(x-2)+2\sqrt{3}(x+1)=6\sqrt{3}\\ \sqrt{3}x-2\sqrt{3}+2\sqrt{3}(x+1)=6\sqrt{3}\\ -2\sqrt{3}+\sqrt{3}x+2\sqrt{3}x+2\sqrt{3}=6\sqrt{3}\\ 1\sqrt{3}x+2\sqrt{3}x=6\sqrt{3}\\ (1+2)\sqrt{3}x=6\sqrt{3}\\ 3\sqrt{3}x=6\sqrt{3}\\ \sqrt{3}x=\frac{6\sqrt{3}}{3}\\ \sqrt{3}x=2\sqrt{3}\\ x=\frac{2\sqrt{3}}{\sqrt{3}}\\ x=2[/tex]