Question

3^x+3^x-1+3^x-2+3^x-3=40​

Answer 1

Răspuns:

Dam factor comun 3 la puterea x:

${3}^{x - 3} ( {3}^{3} + {3}^{2} + 3 + 1) = 40$

${3}^{x - 3} \times 40 = 40$

${3}^{x - 3} = 1$

${3}^{0} = 1$

$x = 3 + 0 = 3$