Question

3(x+4)= 4(y +3)
2(x - 2)= y +1
metoda reducerii va rog repede dau coroana​

Answer 1

Răspuns:

3x+12=4y+12<=>3x-4y=12-12<=>3x-4y=0

2x-4=y+1<=>2x-y=1+4<=>2x-y=5/(-4)<=>-8x+4y=-20

3x-4y=0 x=4

-8×+4y=-20 3×4-4y=0<=>-4y=-12<=>y=3

____________

-5x=-20<=>x=4