Question

31 Dacă a = 8 şi b + c = 17, calculaţi:
a) 2a + 2b + 2c; b) 3a + 2b + 2c;
c) 2b + 20 - 20; d) 3b + 3c-a.

Answer 1

Răspuns:

a) 2a+2b+2c=2(a+b+c)+2(8+17)=2•25=50

b)3a+2b+2c=3a+2(b+c)=3•8+2•17=24+34=58

d) 3b+3c-a=3(b+c)-a=3•17-8=51-8=43

La c) nu ai scris cerința corect.