Question

Cine mă ajută la acest ex??

Answer 1

Explicație pas cu pas:

a) PB = BC = CP => ΔPBC echilateral

∢PBC = ∢PCB = 60°

∢ABP = ∢ABC - ∢PBC

∢ACP = ∢ACB - ∢PCB

=> ∢ABP = ∢ACP

ΔABC isoscel => AB = AC

=> ΔABP = ΔACP (cazul L.U.L.)

b) ∢B = ∢C = 2(∢A)

2(∢A) + 2(∢A) + ∢A = 180°

∢A = 180° ÷ 5 = 36°

∢B = ∢C = 72°

∢ACP = ∢ACB - ∢PCB = 72° - 60 ° = 12°

∢CAP = ∢A ÷ 2 = 36° ÷ 2 = 18°

∢APC = 180° - (∢ACP + ∢CAP) = 180° - (12° + 18°) = 150°

∢ACP = 12°

∢CAP = 18°

∢APC = 150°

Answer 2

Răspuns:

a) m<A=x; m<B=m<C=2x

2x+2x+x=180°

5x=180°

x=36°

2x=72°

PB=BC=CP==>∆PBC-echilateral==>

m<(PBC)=m<(PCB) =60°

==> m<(PBA)=m<(PCA)=72°-60°=12°

PA=PA

AB=AC==> caz U.L.U

==> ∆PAB~∆PAC

b) m<(APC)= 180-12-18=150°