Question

31 Dacă a = 8 şi b + c = 17, calculaţi:
a) 2a + 2b + 2c; b) 3a + 2b + 2c;
c) 2b + 2c - 2a; d) 3b + 3c - a. Va rog!!! Dau coroana!!!!!!

Answer 1

Răspuns:

a) 2a+2b+2c=2(a+b+c)=2(8+17)=2×25=50

b)3a+2b+2c=3×8+2(b+c)=24+2×17=24+34=58

c)2b+2c-2a=2(b+c-a)=2(17-8)=2×9=18

D) 3b+3c-a=3(b+c)-a=3×17-8=51-8=43