Question

[3²×3³+2la puterea54:2la puterea 52+(3la puterea5) ⁴:3la puterea 20] :31​

Answer 1

[3^2 * 3^3 + 2^54 : 2^52 + (3^5)^4 : 3^20] : 31 = (3^5 + 2^2 + 3^20 : 3^20) : 31 = (243 + 4 + 1) : 31 = 248 : 31 = 8

Answer 2

Răspuns:

Explicație pas cu pas:

[3² x 3³ + 2⁵⁴ : 2⁵² + ( 3⁵)⁴ : 3²⁰ ] : 31 = 8

= ( 3⁽²⁺³⁾ + 2⁽⁵⁴⁻⁵²⁾ + 3⁽⁵ˣ⁴⁾⁻²⁰ ) : 31 =

= ( 3⁵ + 2² + 3⁽²⁰⁻²⁰⁾ ) : 31 =

= ( 243 + 4 + 3⁰ ) : 31 =

= ( 247 + 1 ) : 31 =

= 248 : 31 =

= 8