Question

[3la puterea 48:3la puterea 18+(2⁴)la puterea5 +6²³:6¹³]:[(3la puterea 5) ²×(2²)la puterea5 +3la puterea 17×3¹³+(2la puterea5) ⁴]

Answer 1

[3^48 : 3^18 + (2^4)^5 + 6^23 : 6^13]  : [(3^5)^2 * (2^2)^5 + 3^17 * 3^13 + (2^5)^4] = (3^30 + 2^20 + 6^10) : (3^10 * 2^10 + 3^30 + 2^20) = (3^30 + 2^20 + 6^10) : (3^30 + 2^20 + 6^10) = 1