Question

(3supra2+4supra3+5supra4) total la 4 •(2supra4- 1supra4 - 1supra6 - 1supra12) este legal cu

Answer 1

$( \frac{3}{2} + \frac{4}{3} + \frac{5}{4} ) ^{4} * ( \frac{2}{4} - \frac{1}{4} - \frac{1}{6} - \frac{2}{12} )=$
tex]( \frac{3}{2} + \frac{4}{3} + \frac{5}{4} ) ^{4} * ( \frac{1}{4} - \frac{1}{6} - \frac{2}{12} )=[/tex]
tex]( \frac{3}{2} + \frac{4}{3} + \frac{5}{4} ) ^{4} * $\frac{1*3 -1*2 -1}{12}$
tex]( \frac{3}{2} + \frac{4}{3} + \frac{5}{4} ) ^{4} * 0 = 0