Question

(3x+1)²=6(x+3 radical din 2)+28 este:?​

Answer 1

Răspuns:

$9{x}^{2} + 6x + 1 = 6x + 18 \sqrt{2} + 28$

$9x^{2} + 6x - 6x = 18 \sqrt{2} + 28 - 1$

$9x {}^{2} = 18 \sqrt{2} + 27$

$x {}^{2} = \frac{18 \sqrt{2} }{9} + 27 \div 9$

$x {}^{2} = 2 \sqrt{2} + 3$

$x = + - \sqrt{2 \sqrt{2} + 3}$