Question

(3x-4)(3x+4) =
(2y+3) la puterea 2=
(3n-4) la puterea 2
va rog urgent

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Answer 1

Răspuns:

$(3x - 4)(3x + 4)={9x}^{2} - 16$

${(2y + 3)}^{2} = {4y}^{2} + 12y + 9$

$(3n - 4 {)}^{2} = 9 {n}^{2} - 24n + 16$

Answer 2

Răspuns:

Explicație pas cu pas:

$\boxed {(a - b)(a + b) = {a}^{2} - {b}^{2}}$

$\boxed {(a \pm b)^{2} = {a}^{2} \pm 2ab + {b}^{2}}$

$(3x-4)(3x+4) = (3x)^{2} - 4^{2} = 9x^{2} - 16$

$(2y+3)^{2} = (2y)^{2} + 2 \cdot 2y \cdot 3 + 3^{2} = 4y^{2} + 12y + 9$

$(3n-4)^{2} = (3n)^{2} - 2 \cdot 3n \cdot 4 + 4^{2} = 9n^{2} -24n + 16$