Question

3x(x-5)-2(x+2(x-2)=(x+4)(x+1)-16

Answer 1

$3x(x - 5) - 2(x + 2)(x - 2) = (x + 4)(x + 1) - 16$

$3 {x}^{2} - 15x - 2( {x}^{2} - 4) = {x}^{2} + x + 4x + 4 - 16$

$3 {x}^{2} - 15x - 2 {x}^{2} + 8 = {x}^{2} + x + 4x + 4 - 16$

$3 {x}^{2} - 2 {x}^{2} - {x}^{2} - 15x - x - 4x = 4 - 16 - 8$

$- 20x = - 20 \: | \div ( - 20)$

$x = 1$

Answer 2

3x(x-5)-2(x+2)(x-2)=(x+4)(x+1)-16

3x² - 15x - 2x² + 8 = x² + x + 4x + 4 - 16

x² - 15x + 8 = x² + 5x - 12

x² - 15x - x² - 5x = - 12 - 8

-20x = - 20

x = - 20 : - 20

x = 1