Question

3x6,023x10la puterea 23 molecule vor fi cuprinse in:
a. 3 moli de HCL  b. 132 gCO2   c.  67,21 O2 d.  0,051 Kg NH3

Answer 1

Transformi fiecare masa in moli pt ca sti ca intr-un mol de orice subst se afla 6,023 * 10 la 23 molecule
a)x moli........3 * 6,023 
   1 mol.........6,023          x=3 adevarat,corect pt ca ai 3 moli HCl
b)1 mol..........6,023
   y moli .........3 * 6,023        y=3 moli adevarat pt ca 132/44=3 moli CO2
c)1 mol......6,023
   z mol.........3 * 6,023       z = 3 moli adevarat pt ca 67,2/22.4 = 3 moli O2
d)1 mol.......6,023
   a moli........3 * 6.023        a=3 moli adevarat pt ca 51/17=3 moli NH3