Question

(4⁰ +4¹ +4²)⁵:21⁴+ 21⁰​

Answer 1

Răspuns: $\bf\purple{22}$

Explicație pas cu pas:

$\bf\big(4^0 +4^1 +4^2\big)^5:21^4+ 21^0=$

$\bf\big(1 +4 +16\big)^5:21^4+ 1=$

$\bf21^5:21^4+ 1=$

$\bf21^{5-4}+ 1=21^1+1=21+1=\purple{\underline{22}}$

$\red{\bf \underline{Formule~pentru~puteri}:}$

$\bf a^{0} = 1;$

$\bf (a^{n})^{m} = a^{n \cdot m};$

$\bf a^{n}\cdot a^{m} =a^{n+m};$

$\bf a^{n}: a^{m} =a^{n-m}$

==pav38==

Baftă multă !

Answer 2

21 la puterea 0=1

21+1=22