Question

4+8+12+.......+4024=2m*(m+1)
m=?
DAU CORONITAA <3

Answer 1

[tex]4+8+12+ ... +4024 =4(1+2+3+ ... +1006) =4\cdot\dfrac{1006\cdot1007}{2} \\\;\\ =2\cdot1006\cdot1007[/tex]


Expresia din enunt devine:

2·1006·1007 =2·m·(m+1) ⇒ m = 1006

Answer 2

Daca dam factor comun pe 4 obtinem :
 4(1+2+3+....+1006) ; aplicand formula $\frac{m(m+1)}{2}$
=>$4* \frac{m(m+1)}{2} =\ \textgreater$=>se simplifica  4 si 2 =>$2m(m+1)$-->2*1006*1007
Asa ca; aflam ca m=1006