Question

4.Calculati
a) numărul de moli corespunzător la
-100g Al(OH)3,
3,5 g HNO (acid azotic)
b)Cáte grame corespund la 2 moli Ca(OH)2
(H-1, O=16, Al=27, N=14, , Ca=40, )​

Answer 1

Răspuns:

Explicație:

a.

n= m : M

M= 27 + 3.16 + 3= 78------>78g/moli Al(OH)3

n= 100g : 78g/moli = 1,28 moli Al(OH)3

MHNO3= 1+14 + 3.16= 63-------> 63g/moli

n= 3,5g : 63g/moli=0,0055 moli HNO3

b.

m= n . M

MCa(OH)2= 40 + 2.16 +2= 74------> 74g/moli

m= 2moli .74g/moli= 148 g Ca(OH)2