Question

4.calculati:c)[1,(3)]³;d)[1,(6)]³.trebuie cu rezolvare!

Answer 1

[1,(3)]³=[(13-1)/9]³=[12/9]³=[4/3]³=64/27=2,(370)

[1,(6)]³=[(16-1)/9]³=[15/9]³=[5/3]³=125/27=4,(629)

Answer 2

c) (1 intreg 3/9)la puterea a 3-a egal {introducem intregul in fractie} 1728/729 egal 2 intreg si 280/729
d) (15/9) la puterea a treia egal 3375/729 egal 4 intreg si 459/729