Question

4. Calculați cît mai simplu
$\sqrt{ {68}^{2} - {32}^{2} } .$
va rog frumosss​

Answer 1

FORMULE :

$a^{2} -b^{2} = (a+b)(a-b)$

$\sqrt{a*b} = \sqrt{a} * \sqrt{b}$

$68^{2} - 32^{2} = (68-32)(68+32) = 36*100$

$\sqrt{68^2-32^2} = \sqrt{36*100} = \sqrt{36} * \sqrt{100} = 6*10=60$