Question

4.calculati:e)3,1(6)-2 intreg 5 supra 6;f)5 intreg 1 supra 6-4,8(3),dau coroana la primul raspuns!

Answer 1

e)(316-31)/90-(2×6+5)/6=
285/90-(12+5)/6=
57/18-17/6=
19/6-17/6=
(19-17)/6=
2/6=
1/3
f)(5×6+1)/6-(483-48)/90=
(30+1)/6-435/90=
31/6-87/18=
31/6-29/6=
(31-29)/6=
2/6=
1/3