Question

4. Efectuează în două moduri.
a) (7 + 8) x 5
b) 4x (9 + 3 + 1)
(5+6)x 7
5x (3 +8+4)
c) (10 - 6)*5
(9 - 7) x 8
d) 6x (9-2)
8x (7-3)​

Answer 1

Răspuns:

mod 1 A) (7+4)×5 mod 2 5×7+5×4

11×5=55 35+20=55

B) 4×(9+3+1) 4×9+4×3+4×1

4×13=52 36+12+4=52

(5+6)×7 7×5+7×6

11×7=77 35+42=77

5×(3+8+4) 5×3+5×8+5×4

5×15=75 15+40+20=75

C) (10-6)×5 10×5-6×5

4×5=20 50-30=20

(9-7)×8 9×8-8×7

2×8=16 72-56=16

D) 6×(9-2) 6×9-6×2

6×7=42 54-12=42

8×(7-3) 8×7-8×3

8×4=32 56-24=32