Question

4 k+1,4 k+1,(5) k=? k va roooog un raspuns rapid!

Answer 1

$4k+1 \frac{4}{10}k+1 \frac{5}{9} =4k+ \frac{7}{5}k+ \frac{14}{9} k= \frac{180k+63k+70k}{45} = \frac{313}{45} k$

Answer 2

incepem  prin transformarea fractiei periodice 1,(5)=$\frac{15-1}{9}$ = $\frac{14}{9}$ (la numarator, scazi  din numarul scris fara virgula partea dinaintea perioadei)

transformi si 1,4 in fractie: $\frac{14}{10}$

deci avem:4k + $\frac{14}{10}$ + $\frac{15-1}{9}$ aducem la acelasi numitor, care este 90
deci$\frac{360k +126k+140k}{90}$ = $\frac{626k}{90}$ = $\frac{313k}{45}$