Question

4 la puterea 26 supra 32 la puterea 11​

Answer 1

Salut,

$\dfrac{4^{26}}{32^{11}}=\dfrac{(2^2)^{26}}{(2^5)^{11}}=\dfrac{2^{2\cdot 26}}{2^{5\cdot 11}}=\dfrac{2^{52}}{2^{55}}=2^{52-55}=2^{-3}}=\dfrac{1}{2^3}=\dfrac{1}8.$

Ai înțeles rezolvarea ?

Green eyes.