Question

4+ log in baza 2 din 0,25=? ;

Answer 1

$4 + log_{2}(0.25) \\ = log_{2}(16) + log_{2}( \frac{25}{100} ) \\ = log_{2}(16) + log_{2}( \frac{1}{4} ) \\ = log_{2}(16 \times \frac{1}{4} ) \\ = log_{2}( \frac{16}{4} ) \\ = log_{2}(4) \\ = 2$

Answer 2

log baza 2 d in0,25 = log baza 2 din(1/4)
 = log baza 2 din(4 la -1) 
= log baza 2 din(2 la -2) = -2
Rasp: 4 - 2 = 2