Question

4/radical 20+radical 12

Answer 1

$\bf 4 \sqrt{20} + \sqrt{12} =$

$\bf 4 \sqrt{{2}^{2} \cdot5 } + \sqrt{{2}^{2} \cdot3 } =$

$\bf 4\cdot2\sqrt{5 } + 2\sqrt{3} =$

$\boxed{\bf 4\cdot(4\sqrt{5} + \sqrt{3 } )}$