Question

40 g. Zinc reactioneaza cu 200 g solutie de acid clorhidric de concentratie 10%
Calculati: a) M ClZn formata
B) volumul de hidrogen degajat

Answer 1

Cp=md/ms*100⇒md=10*200/100=20g HCl

n=m/M=20/36,5=0,54794 moli HCl

n=m/M=40/65=0,61538g Zn

Zn + 2HCl = ZnCl₂ + H₂

73g HCl...............136g ZnCl₂
20g HCl.................x=37,26g

73g HCl....................2gH
20g HCl....................x=0,54794g H2

n=m/M=0,54794/2=0,273972 moli H2

n=V/Vm=>V=n*M=0,273972*22,4=6,13698 L H2