Question

(493÷17-(128÷2 la puterea a 3 +224÷8)÷22)÷27-1

Answer 1

493÷17=29

2 la puterea a 3 a =8⇒128÷8=16

224÷8=28

(29-(16+28)÷22)÷27-1=(29-44÷22)÷27-1⇒(29-2)÷27-1=27÷27-1=  1-1=0

Answer 2

$(29-(2^{4}+28)/22)/27-1\\ (29-44/22)/27-1\\(29-2)/27-1\\1-1=0 \\sau \\\\1.128/2^{3} =2^{7} /2^{3} =2^{7-3} =2^{4}= 16\\2.224/8=28\\3.16+28=44\\4.493/17=29\\5.44/22=2\\6.29-2=27\\7.27/27=1\\8.1-1=0\\S=[0]$