Question

(4radical 5 supra 5 - 3 supra radical20) : (3 supra radical 20) totul la pterea -1 ...............ajutati-ma , va rog mult

Answer 1

(4√5/5 - 3/√20) : (3/√20)^-1=
=(4x5 - 3/10) : (3/10)^-1
=(20/5-3/10) : (3/10)^-1
=(40/10-3/10) : 10/3
=37/10 : 10/3
=37/10 x 3/10
=111/100
=1,11