Question

4x la 2=(8+4 radical din trei)*radical din( 7-4 radica din 3)

Answer 1

4x²=(8+4√3)·√(7-4√3)
√(7-4√3)=√(7-√48)
$\sqrt{7- \sqrt{48} } = \sqrt{ \frac{7+ \sqrt{49-48} }{2} } - \sqrt{ \frac{7- \sqrt{49-48} }{2} }$
$\sqrt{7- \sqrt{48} } = 2- \sqrt{3}$

4x²=(8+4√3)·(2-√3)
4x²=16-8√3+8√3-12
4x²=4
x²=1
x₁=1
x₂=(-1)